root / ase / test / emt.py @ 13
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1 | 1 | tkerber | import numpy as np |
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2 | 1 | tkerber | from ase.calculators.emt import EMT |
3 | 1 | tkerber | from ase import Atoms |
4 | 1 | tkerber | |
5 | 1 | tkerber | a = 3.60
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6 | 1 | tkerber | b = a / 2
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7 | 1 | tkerber | cu = Atoms('Cu',
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8 | 1 | tkerber | positions=[(0, 0, 0)], |
9 | 1 | tkerber | cell=[(0, b, b),
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10 | 1 | tkerber | (b, 0, b),
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11 | 1 | tkerber | (b, b, 0)],
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12 | 1 | tkerber | pbc=1,
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13 | 1 | tkerber | calculator=EMT()) |
14 | 1 | tkerber | e0 = cu.get_potential_energy() |
15 | 1 | tkerber | print e0
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16 | 1 | tkerber | |
17 | 1 | tkerber | cu.set_cell(cu.get_cell() * 1.001, scale_atoms=True) |
18 | 1 | tkerber | e1 = cu.get_potential_energy() |
19 | 1 | tkerber | V = a**3 / 4 |
20 | 1 | tkerber | B = 2 * (e1 - e0) / 0.003**2 / V * 160.2 |
21 | 1 | tkerber | print B
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22 | 1 | tkerber | |
23 | 1 | tkerber | for i in range(4): |
24 | 1 | tkerber | x = 0.001 * i
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25 | 1 | tkerber | A = np.array([(x, b, b+x), |
26 | 1 | tkerber | (b, 0, b),
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27 | 1 | tkerber | (b, b, 0)])
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28 | 1 | tkerber | cu.set_cell(A, scale_atoms=True)
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29 | 1 | tkerber | e = cu.get_potential_energy() - e0 |
30 | 1 | tkerber | if i == 0: |
31 | 1 | tkerber | print i, e
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32 | 1 | tkerber | else:
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33 | 1 | tkerber | print i, e, e / x**2 |
34 | 1 | tkerber | |
35 | 1 | tkerber | A = np.array([(0, b, b),
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36 | 1 | tkerber | (b, 0, b),
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37 | 1 | tkerber | (6*b, 6*b, 0)]) |
38 | 1 | tkerber | R = np.zeros((2, 3)) |
39 | 1 | tkerber | for i in range(1, 2): |
40 | 1 | tkerber | R[i] = i * A[2] / 6 |
41 | 1 | tkerber | print (Atoms('Cu2', positions=R, |
42 | 1 | tkerber | pbc=1, cell=A,
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43 | 1 | tkerber | calculator=EMT()).get_potential_energy() - 2 * e0) / 2 |
44 | 1 | tkerber | |
45 | 1 | tkerber | A = np.array([(0, b, b),
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46 | 1 | tkerber | (b, 0, b),
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47 | 1 | tkerber | (10*b, 10*b, 0)]) |
48 | 1 | tkerber | R = np.zeros((3, 3)) |
49 | 1 | tkerber | for i in range(1, 3): |
50 | 1 | tkerber | R[i] = i * A[2] / 10 |
51 | 1 | tkerber | print (Atoms('Cu3', positions=R, |
52 | 1 | tkerber | pbc=1, cell=A,
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53 | 1 | tkerber | calculator=EMT()).get_potential_energy() - 3 * e0) / 2 |
54 | 1 | tkerber | |
55 | 1 | tkerber | A = np.array([(0, b, b),
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56 | 1 | tkerber | (b, 0, b),
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57 | 1 | tkerber | (b, b, 0)])
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58 | 1 | tkerber | R = np.zeros((3, 3)) |
59 | 1 | tkerber | for i in range(1, 3): |
60 | 1 | tkerber | R[i] = i * A[2]
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61 | 1 | tkerber | print (Atoms('Cu3', positions=R, |
62 | 1 | tkerber | pbc=(1, 1, 0), cell=A, |
63 | 1 | tkerber | calculator=EMT()).get_potential_energy() - 3 * e0) / 2 |